Question

solve for 1/tan3xtanx​

Answer 1

Step-by-step explanation:

Dear student,

tan3x × tanx =1use tan3x =3tanx−tan3x1−3tan2x3tanx−tan3x1−3tan2x × tanx =13tan2x−tan4x =1−3tan2xtan4x−3tan2x −3tan2x+1=0tan4x−6tan2x +1=0let tan2x =yy2−6y+1=0y = 6±36−4√2y = 6±32√2y = 6±42√2 = 3±22√tan2x =3±22√tanx = ±3±22√−−−−−−−√then x = tan−13+22√−−−−−−−√, x = tan−13−22√−−−−−−−√, x = tan−1(−3+22√−−−−−−−√), x = tan−1(−3−22√−−−−−−−√)

Hope this information will clear your doubts.

Answer 2

Step-by-step explanation:

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