Question

5. In the given figure, BE and CF are two
equal altitudes of AABC.
Show that (i) AABE = AACF,
A
F
E
(ii) AB = AC.
B
С
ADBC are two isosceles triangles​

Answer 1

Answer:

Step-by-step explanation:

BE and CF are two equal altitudes of a triangle ABC . Using RHS congruence rule , prove that the triangle ABC is isosceles . Given: Given BE is a altitude, So, ∠AEB = ∠CEB= 90∘ Also, CF is a altitude, So, ∠AFC = ∠BFC= ... CBE ∴ ∠FBC= ∠ECB So, ∠ABC = ∠ACB AB = AC So, ∆ABC is an isosceles triangle.