5. In the given figure, PQRS is a rhombus and its diagonals intersect at O.
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We know in Rhombus all sides are equal and their diagonals when intersect makes 90°.
∆ROQ Will be Congruence to ∆ROS (Because, SR = QR, Angle SOR = angle ROQ =90° , And hypotenuse SR= QR)
n) since they're congruence so angle ORQ = angle ORS
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