Question

5 joule of
work is done in moving
12.5 X10^ 8 electron from one end to
Other
end
of the
conductor. What
is the potential difference between
the two conductor?​

Answer 1

Answer:-

The potential difference is - 2.5 V

Work down in carrying a charge from one point to another is mathematically represented as -

W = QV

In the equation, w is work done, q is charge and V is potential difference.

In the question, number of electrons are given - 12.5×10^18

Hence, charge being moved is given by -

Q = ne

Q = 12.5×10^18*1.6*10^-19

Q = 2 C

Now, keeping the values in equation-

W = QV

V = W/Q

V = 5/2

V = 2.5 V

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