Question

5 joule of work is done in walking 12.5 into 10 to the power 18 electrons from one end to another end on conductors what is the potential difference the two end of a conductor

Answer 1

V=W/Q=W/ne=5/(12.5×10^18×1.6×10^-19)
=5000/(125×16)=40/16=10/4=2.5v

Answer 2

The potential difference is - 2.5 V

Work down in carrying a charge from one point to another is mathematically represented as -

W = QV

In the equation, w is work done, q is charge and V is potential difference.

In the question, number of electrons are given - 12.5×10^18

Hence, charge being moved is given by -

Q = ne

Q = 12.5×10^18*1.6*10^-19

Q = 2 C

Now, keeping the values in equation-

W = QV

V = W/Q

V = 5/2

V = 2.5 V