Question

5 ka 6 bana do koi plzzz 5 ka 6 (vi)

Answer 1

Hi friend ✋✋✋✋
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Your answer
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To verify : - 0 and 3 are the zeroes of the polynomial p(x) = (x² - 3x)

Now,
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when , P(0) = (0)² - 3 × 0 = 0

So, 0 is a zero of (x² - 3x).

Again,
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When , P(3) = (3)² - 3 × 3 = 9 - 9 = 0

So, 3 is a zero of (x² - 3x).

Therefore,
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Both 0 and 3 are the zeroes of (x² - 3x).

HOPE IT HELPS