Prove that the bisecter of the angles of a linear pair are at right angles
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To prove: Angle A/2 + angle B/2 = 90 degree
Linear pair of angles are supplementary.
Therefore, ∟A + ∟B = 180 0
∟A = A/2 + A/2 [ bisecting linear pairs]
∟ A + ∟ B = 180 0
∟A/2 + ∟A/2 + ∟B/2 + ∟B/2 = 180 0
2 ∟A/2 + 2 ∟B/2 = 180 0
2 [ ∟A/2 + ∟B/2 ] = 180 0
∟A/2 + ∟B/2 = 180/2
∟A/2 + ∟B/2 = 90 0
To prove: Angle A/2 + angle B/2 = 90 degree
Linear pair of angles are supplementary.
Therefore, ∟A + ∟B = 180 0
∟A = A/2 + A/2 [ bisecting linear pairs]
∟ A + ∟ B = 180 0
∟A/2 + ∟A/2 + ∟B/2 + ∟B/2 = 180 0
2 ∟A/2 + 2 ∟B/2 = 180 0
2 [ ∟A/2 + ∟B/2 ] = 180 0
∟A/2 + ∟B/2 = 180/2
∟A/2 + ∟B/2 = 90 0
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