5. kx² - 2✓5x+4 =0 solve by having equal roots
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1
Answer:
Given equation is kx
2
−2
5
+4=0
a=k,b=−2
5
,c=4
∴D=b
2
−4ac=(−2
5
)
2
−4×k×4=20−16
We know that a quadratic equation has real and equal roots, if D=0.
⇒20−16k=0
⇒−16k=−20
⇒k=
16
20
=
4
5
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