Question

5 L of a solution contains 25 mg of Caco3. What is itsconcentration in ppm ? (mol. wt. of CaCO3 is 100)(a) 25(b)1(c)5(d)2500​

Answer 1

Dear Student,

◆ Answer - (C)

Concentration = 5 ppm

● Explaination -

# Given -

Weight of 5 L solution = 5 kg = 5000 g

Weight of CaCO3 = 25 mg = 25×10^-3 g

# Solution -

Concentration of CaCO3 in ppm is calculated by -

Concentration = W(CaCO3)/W(Solution) × 10^6

Concentration = 25×10^-3 / 5000 × 10^6

Concentration = 5 ppm

Therefore, conc of solution is 5 ppm.

Thanks dear. Hope this helps you...

Answer 2

Answer:

This is your answer

Explanation: