Question

5.
Let ABC be a triangle such that AB - (1 - 1) cm, AC-2/x cm, BC = (x+1) cm. Then
A 90°
B 90°
C90°
none of these
​

Answer 1

Answer:

We are given that in △ABC,∠=90

o

tyhe sides of △ABC is given by

AB=x cm,BC=(4x+4)cm &

AC=(4x+5) cm

From the pythagoras theorem,

AC

2

=AB

2

+BC

2

So,

(4x+5)

2

−(x)

2

+(4x+4)

2

16x

2

+40x+25=x

2

+16x

2

+22z−16

∴ 16x

2

+40x+25=17x

2

+32x+16

∴ x

2

−8x−9=0

∴ (x−9)(x+1)=0

∴ x=9 or x=−1

but distance cannot be negative

So, x=9

Now, sides are AB=x=9 cm

BC=4(9)+4=40 cm

AC=4(9)+5=41 cm

Answer 2

Answer:

none of these

Step-by-step explanation:

there if AB= 0cm

then triangle cannot be formed