Question

5 litres of wine replaced from a filled
container of oil and filled with water.
It is repeated again. Now the ratio
of wine and water becomes
25 : 11. Find the capacity of time
container ? with solutions ​

Answer 1

Answer:

56usg+×25737@agx253+272

Answer 2

Answer:

If 5 litres of wine was replaced from a filled container of oil and filled with water twice then the capacity of wine container is 30 litres.

Step-by-step explanation:

Let the capacity of the wine container or the original quantity of wine in the container be “x” litres.

Then,

The quantity of wine left in the container after 2 operations = x[1 – ]²

The new ratio of wine to water is given as = 25 : 11

Now, in order to get the original quantity of juice we will write an eq. as,

[Quantity of juice left in the vessel] / [Original quantity of juice in the vessel] = [New quantity of juice]/ [Total quantity of mixture]

∴ [x{1 – }²] / x =  25/[25+11]

⇒ {1 – }² =  

⇒ {1 – }² =  

Taking square roots on both sides  

⇒  1 -  

⇒ 6[x - 5] = 5x

⇒ 6x - 30 = 5x

⇒ 6x - 5x = 30

⇒ x = 30 litres

Thus, the capacity of wine container is 30 litres.

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8 litres are drawn from a cask full of wine and is then filled with water. this operation is performed three more times. the ratio of the quantity of wine now left in cask to that of water is 16 : 65. how much wine did the cask hold originally  

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In a vessel, there are 10 liters of alcohol. An operation is defined as taking out five liters of what is present in the vessel and adding 10 liters of pure water to it. What is the ratio of alcohol to water after two operations ?  

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Step-by-step explanation:

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