Question

5 men and 4 women are to be seated in a row so that the women occupy the even places . How many such arrangements are possible?
A) 2880
B) 1440
C) 720
D) 2020

Answer 1

5 men and 4 women are to be seated in a row so that the women occupy the even places . How many such arrangements are possible?

A) 2880
B) 1440
C) 720
D) 2020

Answer:   A) 2880 

Read Description:

There are total 9 places out of which 4 are even and rest 5 places are odd.
 
4 women can be arranged at 4 even places in 4! ways.
 
and 5 men can be placed in remaining 5 places in 5! ways.
 
Hence, the required number of permutations  = 4! x 5! = 24 x 120 = 2880

Answer 2

Heyy mate ❤✌✌❤

Here's your Answer....

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There are total 9 places out of which 4 are even and rest 5 places are odd.

4 women can be arranged at 4 even places in 4! ways.

and 5 men can be placed in remaining 5 places in 5! ways.

Hence, the required number of permutations  = 4! x 5! = 24 x 120 = 2880.
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