Question

How many 6-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 so that the digits should not repeat and the second last digit is even ?
A) 521
B) 720
C) 420
D) 225

Answer 1

Q:

How many 6-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 so that the digits should not repeat and the second last digit is even ?

A) 521
B) 720
C) 420
D) 225

Answer:   B) 720 

Read description:

Let last digit is 2

when second last digit is 4 remaining 4 digits can be filled in 120 ways, similarly second last digit is 6 remained 4 digits can be filled in 120 ways.

so for last digit = 2, total numbers=240
 
Similarly for 4 and 6

When last digit = 4, total no. of ways =240
and last digit = 6, total no. of ways =240

so total of 720 even numbers are possible.

Answer 2

Heyy mate ❤✌✌❤

Here's your Answer....

⤵️⤵️⤵️⤵️⤵️⤵️

Let last digit is 2
when second last digit is 4 remaining 4 digits can be filled in 120 ways, similarly second last digit is 6 remained 4 digits can be filled in 120 ways.

so for last digit = 2, total numbers=240

Similarly for 4 and 6
When last digit = 4, total no. of ways =240
and last digit = 6, total no. of ways =240

so total of 720 even numbers are possible.
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