Question

5 ml of N HCl, 20 ml of N/2 H₂SO₄ and 30 ml of N/3 HNO₃
are mixed together and volume made to one litre. The
normality of the resulting solution is
(a) N/5 (b) N/10 (c) N/20 (d) N/40

Answer 1

The normality of the solution is N / 40.

Option (D) is correct.

Explanation:

As we know M(eq) = N x V

Where

• M(eq) = equivalent molarity
• N = normality of solution
• V = volume of solution

Applying this formula for each we get

For HCl----------M(eq) = 1 x 5 = 5 M

For H₂SO₄---------M(eq) =  1/2 x 20 = 10 M

For HNO₃----------M(eq) = 1/3 x 30 = 10 M

For total soluion, M(eq) = M₁ + M₂ + M₃

M(eq) = 5 + 10 + 10 = 25M

and volume = 1000 mL

Applying same formula M(eq) = N x V

25 = N x 1000

N = 25 / 1000

Normality = 0.04 N

Thus the normality of the solution is N / 40.

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