Math, asked by sharanyakumaresanece, 4 months ago

5. Mohan and Sohan went to a bakery shop. Mohan
bought six puffs, four burgers and three cakes and
used up all the money he had. Sohan bought three
puffs, eight burgers and six cakes and spent 20%
more than Mohan. What percent of his money did
Mohan spend on puffs?

Answers

Answered by reeha123
1

Answer:

6p+4b+3c)(1.2)=(3p+8b+6c)=3p+2(4b+3c)

So, if Mohan spent 2x on puffs and y on the others,

(2x+y)(6/5)=x+2y

6(2x+y)=5(x+2y)

12x+6y=5x+10y

7x=4y

y = 7x/4

Now, we want

x/(2x+y) = x/(2x+7x/4)

= x/(15x/4)

= 4/15

Mohan spent 8/15=53.3% of his money on puffs.

check:

(8/15+7/15)(6/5) = 4/15+2(7/15)

Answered by sakshiprabhakar9c
0

Answer:

(6p+4b+3c)(1.2)=(3p+8b+6c)=3p+2(4b+3c)

So, if Mohan spent 2x on puffs and y on the others,

(2x+y)(6/5)=x+2y

6(2x+y)=5(x+2y)

12x+6y=5x+10y

7x=4y

y = 7x/4

Now, we want

x/(2x+y) = x/(2x+7x/4)

= x/(15x/4)

= 4/15

Mohan spent 8/15=53.3% of his money on puffs.

check:

(8/15+7/15)(6/5) = 4/15+2(7/15)

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