Question

5 mole of gas 300 k expand isothermally from an initial volume of 2.OL to final volume of 6.OL (a) what is the work done by gas ? (R= 8.31 J/mol k) how much heat is supplied of gas​

Answer 1

Answer:

25 KJ

Explanation:

V∝T

V1÷V2=T1÷T2

2÷6=300÷T2

T2=900K

HEAT(Q)=internal energy(U)+work done(W)

here isothermal condition indicates U=0

so W=Q

w=nRΔT

W=5×8.314×(900_300)

W=6000×8.314

W=24.9×1000

W=25 kilojoules