5 moles of Nitrogen is allowed to react with 8 moles of Hydrogen to form ammonia. Which is the limiting reagent? Also calculate the no.of moles of the product formed
Answers
Answer:
First, write the equation describing the reaction you are dealing with.
It is N2 + 3 H2 == 2 NH3.
Then, divide the amount (or number of moles) of each reactant by the corresponding stoichiometric coefficient in the same reaction.
You get 4:1 = 4 for N2 ; 8:3 = 2.67 for H2.
The lowest of these ratio corresponds to the so called limiting reactant; it is the reactant that will be completely used up while amounts of other reactants are still available. Therefore, the maximum amounts of products that can be formed will depend on, and will be in proportion to, the amount of the limiting reactant.
In your case, 2 moles of NH3 will be formed for each 3 moles of H2 available. By a simple proportion, the amount of ammonia that will be formed turns out to be about 5.33 moles.
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