5^n+3 -6*5^n+1/9*5^x-4*5^n
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kilometre an hour at the rate of 12 by 3 kilometre and hour he would have taken 3 hour more to move that distance
Step-by-step explanation:
kilometre per hour faster it would have taken 3 hours less than the scheduled time and if the train was lower by 4 kilometre per hour it would have taken 8 hours more than the scheduled time we find the length of the journey5^n+3 -6*5^n+1/9*5^x-4*5^n
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