5 Newton force is acting on a conductor of length 10cm is placed vertically in a uniform
magnetic field. If 20 amp of current is passing through the conductor , what is the value
of magnetic flux density ?
Answers
Answer:
Hence magnetic flux B = 2.5
Explanation:
As per given information in question statement, we can say that
Force = 5 N,
Current = 20Amperes,
Length = 10cm
Length = 10×10^-2m
The formula for magnetic force experience by a conductor placed in magnetic field is;
Force F =BILsin Θ
sin 90 =1 due to vertical placement
Hence F =BIL
B =F/IL
Putting values in formula;
= 5/20×10×10^-2
= 5×10^2/20×10
= 500/200
= 2.5
Hence magnetic flux B = 2.5
The value of magnetic flux density is 2.5 Tesla.
Given:
Force = F = 5 N
Length = L = 10 cm = 10 × 10⁻² m = 0.1 m
Current = I = 20 A
Explanation:
The magnetic force is given by the formula:
F = BIL sin θ
Where,
θ = Angle between conductor and uniform magnetic field = 90°
On substituting the values, we get,
5 = B × 20 × 0.1 × (sin 90)
5 = B × 20 × 0.1 × 1
5 = B × 2
B = 5/2
∴ B = 2.5 Tesla