If the 5th term of an ap is zero show that its 33rd term is fourtimes its 12th term
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a+4d=0
a+(33-1)d=a+32d
=a+8(4d)
=a+8(-a)
=-7a
a+(12-1)d=4a+44d=4a+11*4d=4a-11a=-7a.
hence proved.
a+(33-1)d=a+32d
=a+8(4d)
=a+8(-a)
=-7a
a+(12-1)d=4a+44d=4a+11*4d=4a-11a=-7a.
hence proved.
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