Question

5 Newton force is acting on a conductor of length 10cm is placed vertically in a uniform

magnetic field. If 20 amp of current is passing through the conductor , what is the value

of magnetic flux density ?​

Answer 1

Answer:

The answer is 2.5 tesla

GIVEN

F=5N

l=10cm=0.1m

I=20A

we know that

F=BIL

5=B*0.1*20

therefore B=2.5 T

Answer 2

Answer: Magnetic flux density is 25Wb/m².

Explanation:

$Force\ acting\ on\ conductor=5N\\Length\ of\ conductor=10 cm\\Current\ passing\ through\ conductor=20Amp$

The conductor is placed vertically in a magnetic field B

$\theta =90^{0}$

$F=(B.i.l).Sin\theta$

$5=B\times 20\times 0.1\times Sin 90^{0}\\B=50/20=2.5\\Magnetic\ flux\ density=Magnetic\ flux/Volume\\Magnetic\ flux\ density=\phi /(A.l)\\=(B.A)/(A.l)=2.5/0.1=25$

$\phi =25Wb/m^{2}$