Question

5 Newton force is acting on a conductor of length 10cm is placed vertically in a uniform magnetic

field. If 20 amp of current is passing through the conductor , what is the value of magnetic flux

density ​

Answer 1

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the 5 newton force is acting on a conductor of length 10cm.If 20 amp passing through the conductor.

Here Force=5,

current=20Amperes,

length=10cm

=10×10^-2m

Force(F)=BILsin teeta(sin 90 =1)

Then F =BIL

B =F/IL

=5/20×10×10^-2

=5×10^2/20×10

=500/200

=5/2

=2.5

Then the value of magnetic flux B = 2.5