5. Number of grams of oxygen in 32.2 g 2 4 2 Na SO H O .10 is a) 20.8 b) 22.4 c) 2.24 d) 2.08
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Explanation:No. of oxygen atoms in one molecule =4+10=14
Thus moles of oxygen in n moles of compound=n*14
Molar mass of Na2SO4.10H2O=46+32+64+180=322g/mol
Thus
32.2g=32.2/322=0.1 mols
Thus moles of O=0.1*14=1.4
So weight is
16*1.4=22.4g
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