Question

5 numbers are arranged in increasing order if the average of first four number is 34 and the average of last four number is 40 what is the difference between first and last number

Answer 1

Answer:

Step-by-step explanation:

let the numbers be a b c d e respectively

according to question

first condition

(a+b+c+d)/4 = 34

(a+b+c+d) = 34*4

(a+b+c+d) = 136     ................... eq-1

second condition

(b+c+d+e)/4 = 40

(b+c+d+e) = 40*4

(b+c+d+e) = 160   ..................... eq-2

from equations 1 & 2, we get

(b+c+d) = 136-a    &  (b+c+d) = 160-e

which implies that

136-a = 160-e

(e-a) = 160 - 136

(e-a) = 24      answer

how you got the solution........ :)

ATB

Answer 2

Answer:

24

Step-by-step explanation:

Let the five numbers be a,b,c,d and e.

According to Question:-

Average of first four number = 34

Average of last four number = 40

As we know:-

Average = sum of all integers/number of integers

So,

Average of 1st four numbers = a+b+c+d/4 = 34

a+b+c+d = 34*4

a+b+c+d = 136------- eq. 1

Average of last four numbers = b+c+d+e/4 = 40

b+c+d+e = 40*4

b+c+d+e = 160---------eq. 2

Subtracting eq. 1 from eq. 2:-

b+c+d+e-(a+b+c+d) = 160-136

b+c+d+e-a-b-c-d = 24

e-a = 24

Hence, the difference between first and last number is "24".

Hope it helps.......