Question

5.
Observe the following picture a
write down the chemical reaction
with explanation.
Collected rust
Water drop
Fe,0, H,0
Fe2+ (aq)
Cathode
e
Anode
0, + 2H,0 + 4€ -> 40H
Fe -> Fe2+ + 2e
0, + 4H+ + 48 -> 2H,0
Iron​

Answer 1

Answer:

(1) Fe is oxidised to Fe2++ in the anode region. Fe(s) gives Fe2+(aq) + 2 e-. (2) O2 is reduced to form water in in the cathode region. ·

Explanation:

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