Question

5% of the population of a certain town was killed in a bombardment and 7% of the remaining died in panic. If the population of the town is now 44175, find the population of the town at the beginning before the bombardment.



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Answer 1

Answer:

3,68,125

Step-by-step explanation:

Total percent killed= 12%

Therefore before the bombardment= 44175/12% = 44175* 100/12 = 3,68,125

Answer 2

Question

1. 5% of the population of a certain town was killed in bombardment and 7% of the remaining died in panic. If the population of the town is now 44175; find the population of the town at the beginning before the bombardment.

To find,

• The population of the town before the bombardment

Solution

$\sf{ Let \: the \: population \: of \: the \: town \: at \: the \: beginning \: be \:100}$

⁂ Population killed in bombardment = 5% of 100 = 5

          Remaining population = 100 - 5 = 95

$\sf{Population \: died \: in \: panic=7 \% \: of 95=\dfrac{7}{100} \times 95=\dfrac{133}{20}$

$\sf{Remaining \: population=95-\dfrac{133}{20}=\dfrac{1767}{20}$

Applying unitary method :-

$\sf{If \: the \: remaining \: population \: is \: \dfrac{1767}{20}, \: population \: at \: the \: beginning=100$

$\sf{If \: the \:remaining \: population \: is \: 1, \: population \: at \: the \: beginning=100 \times \dfrac{20}{1767}$

and, if the remaining population is 44175, population in the beginning

                                   $\sf{= \: 100 \times \dfrac{20}{1767} \times 44175=50,000$

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