Question

√5 on number line by steps​

Answer 1

Answer:

•Draw number line as shown in the figure. Let the point O represent 0(zero) and point A represents 2. Draw perpendicular AX at A on the number line and cut-off arc AB=1unit.

•Draw number line as shown in the figure. Let the point O represent 0(zero) and point A represents 2. Draw perpendicular AX at A on the number line and cut-off arc AB=1unit.We have OA=2 units and AB=1unit

•Draw number line as shown in the figure. Let the point O represent 0(zero) and point A represents 2. Draw perpendicular AX at A on the number line and cut-off arc AB=1unit.We have OA=2 units and AB=1unit•Using pythagoras theorem, we have,

•Draw number line as shown in the figure. Let the point O represent 0(zero) and point A represents 2. Draw perpendicular AX at A on the number line and cut-off arc AB=1unit.We have OA=2 units and AB=1unit•Using pythagoras theorem, we have,OB²=OA² +AB²

•Draw number line as shown in the figure. Let the point O represent 0(zero) and point A represents 2. Draw perpendicular AX at A on the number line and cut-off arc AB=1unit.We have OA=2 units and AB=1unit•Using pythagoras theorem, we have,OB²=OA² +AB² OB²=(2)²+1² =5

•Draw number line as shown in the figure. Let the point O represent 0(zero) and point A represents 2. Draw perpendicular AX at A on the number line and cut-off arc AB=1unit.We have OA=2 units and AB=1unit•Using pythagoras theorem, we have,OB²=OA² +AB² OB²=(2)²+1² =5OB=√5

•Draw number line as shown in the figure. Let the point O represent 0(zero) and point A represents 2. Draw perpendicular AX at A on the number line and cut-off arc AB=1unit.We have OA=2 units and AB=1unit•Using pythagoras theorem, we have,OB²=OA² +AB² OB²=(2)²+1² =5OB=√5 •Taking O as the centre and OB= √5 as radius draw an arc cutting real line at C.

•Draw number line as shown in the figure. Let the point O represent 0(zero) and point A represents 2. Draw perpendicular AX at A on the number line and cut-off arc AB=1unit.We have OA=2 units and AB=1unit•Using pythagoras theorem, we have,OB²=OA² +AB² OB²=(2)²+1² =5OB=√5 •Taking O as the centre and OB= √5 as radius draw an arc cutting real line at C.Clearly, OC=OB= √5

•Draw number line as shown in the figure. Let the point O represent 0(zero) and point A represents 2. Draw perpendicular AX at A on the number line and cut-off arc AB=1unit.We have OA=2 units and AB=1unit•Using pythagoras theorem, we have,OB²=OA² +AB² OB²=(2)²+1² =5OB=√5 •Taking O as the centre and OB= √5 as radius draw an arc cutting real line at C.Clearly, OC=OB= √5 •Hence, C represents √5 on the number line.