5. Out of the total production of Aluminum from
Bauxite, an ore of Aluminum, 30% of the ore gets
wasted, and out of the remaining ore, only 30% is
pure Aluminum. If the pure Aluminum obtained in
a year from a mine of Bauxite was 42,000 kg, then
the quantity of Bauxite mined from that mine in the
year is
Answers
Step-by-step explanation:
let's assume the total production is 100 then,
30% of the ore gets wasted that means,
100x30/100= 70
out of the remaining ore, only 30% is pure aluminum
now,
100x70/100x30/100=42000kg
(100x0.7x0.3)=42000kg
21%= 42000kg
21/100=42000kg
42000x100/21= 200000kg
The quantity of Bauxite mined from that mine in the year is 200000 kg
Given :
- Out of the total production of Aluminum from Bauxite, an ore of Aluminum, 30% of the ore gets wasted, and out of the remaining ore, only 30% is pure Aluminum.
- The pure Aluminum obtained in a year from a mine of Bauxite was 42,000 kg
To find :
The quantity of Bauxite mined from that mine in the year
Solution :
Step 1 of 2 :
Form the equation to find the quantity of Bauxite mined from that mine in the year
Let the quantity of Bauxite mined from that mine in the year = 100q kg
Since out of the total production of Aluminum from Bauxite, an ore of Aluminum, 30% of the ore gets wasted
∴ The percentage of remaining ore
= (100 - 30)%
= 70%
∴ The quantity of remaining ore
Again out of the remaining ore, only 30% is pure Aluminum.
∴ The quantity of pure Aluminum
The pure Aluminum obtained in a year from a mine of Bauxite was 42,000 kg
So by the given condition
Step 2 of 2 :
Calculate the quantity of Bauxite mined from that mine in the year
Hence quantity of Bauxite mined from that mine in the year
= 100q kg
= (100 × 2000) kg
= 200000 kg
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