Question

The sum of 4 consecutive integers is 130
What is the third number in this sequence?

Answer 1

Hey mate

Here's your answer

The answer is 33.

Solution:

Let the nos. be x, x+1, x+2, x+3

x + x +1 + x+2 + x+3 =130

4x + 6=130

4x = 130 - 6

4x = 124

x = 124 ÷ 4

x = 31

x+1=32

x+2=33

x+3=34

Hope it's helpful for you ^-^

Have a good day ☺️

Answer 2

Answer:

let the 4 consecutive integers be x, x+1, x+2, x+3

x + x+1 + x+2 +x+3 = 130 ( given)

4x + 6 = 130

4x = 130-6

4x = 124

x = 124/4

x = 31

so the third number is x + 2

= 31 + 2

=33