5 p q ( p ^ { 2 } - q ^ { 2 } ) \div 2 p ( p + q )
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Answer:5pq(p2-q2)÷2p(p+q).
As we know that a2-b2 = (a-b)(a+b).
Applying same to p2-q2 = (p+q)(p-q).
Now expanding and dividing.
5pq(p2-q2)÷ 2p(p+q).
5pq(p+q)(p-q)/2p(p+q).
p(p+q) will be cancelled out from numerator and denominator, leaving values
5q(p-q)/2.
Or we can also write it as,
5/2pq-5/2q2.
Hope it helps.
Step-by-step explanation:
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