Question

5 Paper 1 Math Annual Exam (6 A)
A square shaped park ABCD of side 100 m has two equal rectangular flower beds each of size
10 mx 5 m (see figure). Perimeter of the remaining park is: *
​

Answer 1

Answer:

Option B is right

For Flower bed given that

Length(l)=10 m

Width(w)=5 m

∴ Perimeter of flower bed =2×(l+w)

=2×(10+5)m

=30 m.

There are two such flower beds.

For each bed, its one length and one breadth lie on boundary of the park.

So, perimeter of both flower bed lying on park=

2

1

(2×primeter of one bed)

=

2

1

(2×30)=30 m

Now, side of square ABCD=100 m

Therefore, perimeter of ABCD=4×100 m=400 m

So, perimeter of remaining area of park=perimeter of ABCD-perimeter of both flower bed lying on park

=400−30=370 m