Question

If vertices of a triangle are (3,6) ,(7,k) and (5,12) and its area is 16 square units, find k​

Answer 1

Step-by-step explanation:

area of triangle =16

1/2×x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=16

1/2×3(k-12)+7(12-6)+5(6-k)=16

1/2×3k-36+42+30-5k=16

1/2×36-2k=16

36-2k=16×2

2(18-k)=16×2

18-k=16

18-16=k

k=2

therefore value of k is 2

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Answer 2

Answer:

area of triangle =16

1/2×x1(y2-y3)+x2(y3-y1)+x3(y1-y2)=16

1/2×3(k-12)+7(12-6)+5(6-k)=16

1/2×3k-36+42+30-5k=16

1/2×36-2k=16

36-2k=16×2

2(18-k)=16×2

18-k=16

18-16=k

k=2

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