5 pencil and 7 pens together cost 50 ,where 7 pencils and 5 pens together cost 46 . find the cost of one pencil and that of one pen
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Let The cost of 1 pencil be X
And cost of 1 pens be Y
According to question
The cost of 5 pencil and 7 pens is 50
So, the equation is.
5x+7y=50....(1)
AGAIN cost of 7 pencil and 5pens is 46
so,7x+5y=46..(2)
BY ELIMINATION method
Multiply equal (1) with7
7(5x+7y)=7×50
35x+49y=350..(3)
================
Multiply equation (2)with 5
5(7x+5y)=5×46
35x+25y=230..(4)
Substrating eq (3)and (4)
we got
35x+49y-(35x+25y)=350-230
35x+49y-35x-25y=120
49y-25y=120
24y=120
y=120/24
y=5
AGAIN÷
replace this in equation (1)
5x+7y=50
5x+7×5=50
5x+35=50
5x=50-35
5x=15
x=15/5
x=3
So the cost of 1 pencil is [tez]\red{\huge{3}}[/tex]
And cost of 1 pens is
:: Thns 4 ur questions::
And cost of 1 pens be Y
According to question
The cost of 5 pencil and 7 pens is 50
So, the equation is.
5x+7y=50....(1)
AGAIN cost of 7 pencil and 5pens is 46
so,7x+5y=46..(2)
BY ELIMINATION method
Multiply equal (1) with7
7(5x+7y)=7×50
35x+49y=350..(3)
================
Multiply equation (2)with 5
5(7x+5y)=5×46
35x+25y=230..(4)
Substrating eq (3)and (4)
we got
35x+49y-(35x+25y)=350-230
35x+49y-35x-25y=120
49y-25y=120
24y=120
y=120/24
y=5
AGAIN÷
replace this in equation (1)
5x+7y=50
5x+7×5=50
5x+35=50
5x=50-35
5x=15
x=15/5
x=3
So the cost of 1 pencil is [tez]\red{\huge{3}}[/tex]
And cost of 1 pens is
:: Thns 4 ur questions::
protestant:
sorry 4 before
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