Question

5. PLAY WITH NUMBERS
A
following
Assignment 41
a If a 'b' and are numbers between 0 and 9, find their value in the


• 100a + 40 + 8 = 600 + 48
b = -
C=
• 700 + 10b + c = 800 – 75
a =
с
• 100a + 60 + C = 300 + 50 + 17
b=_
. 900 + 10b + c = 1000 - 8
a =
b
• 100a + 10b + 9 is a largest 3 digit number so
• 100a+10b + c = 300 + 120
a = _ ,b=_
• 100a+10b + c = 1000 - 347
a =
b=0
100a+10b + c = 500+ 2 + 8
a= b =
C=
• 100a+10b + c = 200 + 227 +31
a = b =_
• 100a+10b + c = (40 x 3) + (11 x 7) a =_b=
. 100a+10b + c = (1000 + 4) - 162 a =___=


(anyone knows this answer then please tell me its answer)​

Answer 1

Answer:

351 = 300 + 50 + 1 = 100 × 3 + 10 × 5 + 1 × 1 497 = 100 × 4 + 10 × 9 + 1 × 7. Similarly, In general, a 3-digit number abc made up of digits a, b and c is written as.

Step-by-step explanation:

Solution to your question is as follows:

Three digit number can be represented as , its reverse number would be or .

Given: --> , this gives us 7 values for and : {9,6}{8,5}{7,4}{6,3}{5,2}{4,1}{3,0}.

Also given: , from above we know , hence --> , only one value for .

So total of 7 such numbers are possible: {916}{815}{714}{613}{512}{411}{310}.

Answer: C.