Question

5 positive integers are in AP. the sum of three middle term is 24. product of first and 5th term is 48.find the terms of AP​

Answer 1

Step-by-step explanation:

Let the 5 +ve integers be

a-3d,a-d,a,a+d,a+3d

sum of middle 3 No's

a-d+a+a+d=24

3a=24

=>a=8

product of first n last term

(a-3d)×(a+3d)=48

a^2-(3d)^2=48

(8^2) - (3^2)(d^2) = 48

64-9d^2=48

-9d^2=48-64

-9d^2 = -16

d^2=16/9

d=4/3

so the required terms of the AP are,,

a-3d=8-3(4/3)=4

a-d=8-4/3=20/3

a=8

a+d=8+4/3=28/3

a+3d=8+3(4/3)=12

therefore, the AP is......

4, 20/3, 8, 28/3, 12