Question

5. Prove that:
(i) sin 0 cos (90° - 0) + sin (90° - 0) cos 0 = 1​

Answer 1

Answer:

Sin 0 cos (90-0)°+sin (90-0)°cos0=1

Sin0sin 0 +cos 0 cos 0 =1

Sin^2+cos^2 0=1

1=1

LHS=RHS

Hence provide