Question

5 resistor of 10 ohm are connected in parallel A current of 1A flows through each other, What will be the current through each of them if they are connected in series? A) 0.5A B)0.2A C)1A D)5A

Answer 1

0.2A is the correct answer

Answer 2

Your answer is B)0.2A

Here is your answer ::-

First we will find potential difference (V)

Total resistance in parallel = 1/R₁ + 1/R₂ + 1/R₃ + 1/R₄ + 1/R₅

= 1/10 + 1/10 + 1/10 + 1/10 + 1/10

= 1/10 x 5

= 5/10

= 1/2

Total resistance in parallel is 2 ohm

R = V/I .......ohm's law

2 = V/1x5 .......there are total 5 resistors of 1A each

V = 2 x 5

V = 10

PD = 10V

If resistors are in series ::-

Total resistance = R₁+ R₂ + R₃ + R₄ + R₅

= 10+ 10 + 10 + 10 + 10

= 50 ohms

So, the total resistance in series is 50 ohms

The PD will be same in the circuit , that is PD = 10V

R = V/I........ohm's law

50 = 10/I

I = 10/50

I =1/5

I = 0.2 A

Therefore the current through the circuit when resistors are in series is 0.2 Ampere.

So, your answer is B) 0.2A

HOPE IT HELPS YOU!!