Question

5+root 3/5-root 3= a+b root 3​

Answer 1

Given :-

Required to find :-

Values of " a " and " b "

Identities used :-

( x + y ) ( x + y ) = ( x + y )²

( x + y ) ( x - y ) = x² - y²

( x + y )² = x² + 2xy + y²

Solution :-

Given information :-

we need to find the values of ' a ' and ' b '

So,

Consider the LHS part

Here,

We need to rationalize the denominator !

So,

Rationalising factor of √5 - √3 = √5 + √3

Hence,

Multiply both numerator and denominator with that factor

So,

Here we need to use some algebraic Identities

They are ,

1. ( x + y ) ( x + y ) = ( x + y )²

2. ( x + y ) ( x - y ) = x² - y²

3. ( x + y )² = x² + 2xy + y²

So,

Using 1 and 2 we get ;

Using the 3rd identity expand the numerator

This implies,

2 gets cancelled in both numerator and denominator

So,

we are left with ;

Now,

Compare the LHS and RHS parts

From the above comparison we can conclude that the LHS in the form of RHS

So,

Equal the values on both sides

Hence,

a = 4

b = 1

Therefore,

Values of " a " and " b " are 4 & 1

Answer 2

Answer:

Step-by-step explanation:

your question is not understand

5+$\sqrt{3}$/5-$\sqrt{3}$=a+b$\sqrt{3}$