Question

5+root3/7+root3= p+qroot3​

Answer 1

Answer:

$5 + \sqrt{ \frac{3}{7} } + \sqrt{3 } = p + q \sqrt{3} \\ 5 + \frac{ \sqrt{3} }{ \sqrt{7} } + \sqrt{3 } = p + q \sqrt{3} \\ 5 + \sqrt{3} ( \frac{1}{ \sqrt{7} } + 1) = p + q \sqrt{3} \\ hence \: \\ p = 5 \ \: and \: \\ q = \frac{1}{ \sqrt{7} } + 1$

$hope \: it \: will \: helpful$