Question

sum of the digits of a two-digit number is 11 when we interchange the digits it is found that the resulting new number is greater than the original number by 63 find the two digit number​

Answer 1

Answer:

required number is 29

Step-by-step explanation:

let the number in tens place be x

and the number in unit place be y

the two digits number is in the form of 10x + y

sum of the digits is 11

x + y = 11 equ (1)

by interchanging the number it is 63 more than the original number

10x + y + 63 = 10y + x

10x + y + 63 - (10y + x) = 0

10x + y - 10y - x = - 63

9x - 9y = - 63

9(x - y) = - 63

x - y = -63/9 = -7

x - y = - 7 equ (2)

from equ (1) & (2)

we get

2x = 4

x = 4/2 = 2

substitute x= 2 in equ (1)

x + y = 11

2 + y = 11

y = 11 - 2

y = 9

therefore the required number is

= 10x + y

= 10(2) + 9

= 20 + 9

= 29

interchanging the digits

= 10y + x

= 10(9) + 2

= 90 + 2

= 92

proof

29 + 63 = 92

hope you get your answer