Question

$could \: u \: plz \: give \: me \: the \: ans$

Answer 1

let the inner radius of the bowl br r1 =5cm
hemisphere bowl has thickness=0.25cm
so, diamter of outer surface =r1+0.25+0.25=5+0.50=5.50cm
now , curved surface area of outer surface=2×pie×rsquare=2×22÷7×5.50×5.50
curved surface area of inner surface=2×22÷7×5×5
now , ratio of outer surface area to inner surface area =(2×22÷7×5.50×5.50)÷(2×22÷7×5×5)
=5.50×5.50/5×5
=1.21:1

Answer 2

I don't know.............