Question

5. sin 2A = 2 sin A is true when A=
(a) 30°
(b) 45°
(c) 0°
(d) 60°​

Answer 1

Answer:

0

Step-by-step explanation:

sin2A=2sinA

⇒2sinAcosA=2sinA

⇒2sinA(cosA−1)=0

⇒sinA=0,cosA−1=0

⇒sinA=0,cosA=1

sinA=0⇒A=0,π,2π

cosA=1⇒A=0,2π

∴A={0,π,2π}∩{0,2π}

={0,2π}

Hence A=0

Answer 2

Answer:

answer is ~0

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