Math, asked by surojitsaha2298, 6 months ago

5(sin^2A+sin ^2 B +sin ^ C)=4 (simASinB+SinB Sin C +SinC sinA) ,then find the value Cos A +Cos B + cos C

Answers

Answered by ma799938

1

which subject ma tell me not

Answered by sritarutvik

0

Step-by-step explanation:

5(sin^2A+sin ^2 B +sin ^ C)=4 (simASinB+SinB Sin C +SinC sinA)

5((1+cos2A)/2+(1+cos2B)/2+(1+cos2C)/2)=2(2sinAsinB+2sinBsinC+sinCsinA)

5(3+cos2A+cos2B+cos2c)/2=2(cos(

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