Question

5 sin²30 + sin² 45 - 4tan²30 ÷ 2sin30 - cos30 + cot 45

Answer 1

Answer:

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

${sin}^{2} 30 + {sin}^{2} 45 - 4 {tan}^{2} 30 \div 2sin30 - cos30 + cot45$

${ (\frac{1}{2} )}^{2} + { (\frac{1}{ \sqrt{2} } )}^{2} - 4 \times { (\frac{1}{ \sqrt{3} } )}^{2} \times1 - \frac{ \sqrt{3} }{2} + 1$

$\frac{1}{4} + \frac{1}{2} - \frac{4}{3} - \frac{ \sqrt{3} }{2} + 1$

$\frac{3 + 6 - 16 - 6 \sqrt{3} + 12}{12}$

$\frac{ - 7 - 6 \sqrt{3} + 12}{12} = \frac{5 - 6 \sqrt{3} }{12}$

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