Question

5 sinx +12 Cosx=13 find tanx​

Answer 1

Answer:

We know that sin²x + cos²x =1

Now dividing both sides by cos²x, we get

tan²x + 1 =     (Equation 1)

Now the given equation is 12cosx+5sinx =13

Dividing both sides by cosx we get,

12 + 5 tanx =  

Squaring both sides, we get

144 + 120 tanx + 25tan²x =      

144 + 120 tanx + 25tan²x = 169(1+tan²x)          (From equation 1)

144 + 120 tanx + 25tan²x = 169+169tan²x

144tan²x - 120 tanx + 25 = 0

(12tanx)² - 2×12tanx×5 + 5² =0

(12tanx-5)²=0

12tanx-5=0

tanx = 5/12

The value of tanx is 5/12.

Explanation:

Answer 2

5/13 it too hard what is the ans