5% solution se3.6%ka solutio kaise banaye
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Explanation:
Dear Sir. Concerning your issue about the preparation of 3.5% soln from 5% . You can use dilution law :
C1*V1 = C2 * V2
assume if you want to prepare to the volume of 100 ml, then:
5 % * V1 = 3.5% * 100 , So , V1= 7 ml, that mean you should take 7ml from the stock solution (5%) and completed to the volume (100ml) by deionized water.
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Answer:
There should be such kind of element in the compound which can become vapour when it undergoes either exothermic or endothermic or heat, etc. So, in order, the percentage of a particular solution goes down.
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