Question

5. Solve for x and y:
139x + 56y = 641; 56x + 139y = 724

Answer 1

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Let the given equations be ;

139x + 56y = 641 -------- (1)

56x + 139y = 724 --------- (2)


On adding eq. 1) & 2) we get ;

195x + 195y = 1365

195(x + y) = 1365 [ on taking 195 as common ]


x + y = 1365/195

x + y = 7 ------- (3)


Now, subtracting eq.2) from 1) we get,

83x - 83y = -83

83 (x - y ) = -83

x - y = -83/83

x - y = -1 ------- (4)



Adding eq.3) and 4) we get ;


2x = 6

x =3

On putting value of "x" in eq.4) we get ;

3-y = -1

y = 4




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Hope it helps☺

Answer 2

$\large {\huge{ \color{green}{ \mathfrak{welcome}}}}$

$\bold{ \huge{ \red{ \fbox{required \: answer}}}}$
139x + 56y = 641 -- (1)

56x + 139y = 724 -- (2)

$\bold{ \huge{ \red{ \fbox{now}}}}$

$\bold{ \huge{ \green{ \fbox{adding \: eqations}}}}$

195x + 195y = 1365
195(x + y) = 1365
x + y = 1365/195
x + y = 7 ---- (3)

$\bold{ \huge{ \blue{ \fbox{subtract \: equations}}}}$

83x - 83y = -83
83(x-y) = -83
x - y = -83/83
x - y = -1 ---- (4)

$\bold{ \huge{ \blue{ \fbox{adding \: eq.3 \: and \: 4}}}}$

2x = 6
x =3

$\bold{ \huge{ \red{ \fbox{subtract \: equation}}}}$
3-y = -1
y = 4

$\bold{ \huge{ \red{ \fbox{answer}}}}$

$\bold{ \huge{ \red{ \fbox{ =)x = 3}}}}$

$\bold{ \huge{ \green{ \fbox{ = )y = 4}}}}$

$\large {\huge{ \color{green}{ \mathfrak{dhanyavaad}}}}$