Question

a man standing on the deck of the ship which is 20m above the sea level observes the angle of elevation of a bird as 30° and the angle of depression of its reflection in the sea ad 60°.find the height of the bird?

Answer 1

Plz mark it brainlist answer.
The answer is 40m above.
Because when we add 5+5=10.
Then,10+30+(5+5)10=50
60+30=90
90-50=40
This is the answer with formula.

Hope it will help you.

Answer 2

Answer:

Height of the bird is 36.67 m

Step-by-step explanation:

Figure is attaches.

Given: AC = DE = 20 m , m∠BAD = 30°   and m∠DAE = 60°

To find: Height of bird that is BE.

In Δ ADE

using trigonometric ratio,

$tan\,60=\frac{DE}{AD}$

$\sqrt{3}=\frac{20}{AD}$

$AD=\frac{20}{\sqrt{3}}$

Now, In Δ ADB

using trigonometric ratio,

$tan\,30=\frac{BD}{AD}$

$\frac{1}{\sqrt{3}}=\frac{BD}{\frac{20}{\sqrt{3}}}$

$BD=\frac{1}{\sqrt{3}}\times\frac{20}{\sqrt{3}}$

BD = 20/3

Height of bird , BE = BD + DE = 20 + 20/3 = 80/3 = 36.67 m (approx.)

Therefore, Height of the bird is 36.67 m