Math, asked by inchara2345, 4 days ago

5. Subtract 4a^3-3a^2b+ab^2-b^2 from a^3+b^3-3a^2+7ab^2​

Answers

Answered by yanbysmarak
2

Answer:

=12a−9ab+5b−3−(4a−7ab+3b+12)

=12a−9ab+5b−3−4a+7ab−3b−12

=8a−2ab+2b−15

hope it helps, have a great day

Answered by mahakulkarpooja615
6

Answer:

a^{3}+b^{3} -3a^{2} +7ab^{2}- 4a^{3} -3a^{2} b+ab^{2} -b^{2} = -3a^{3} +b^{3}-3a^{2}-3a^{2}b  +8ab^{2}  -b^{2}

Step-by-step explanation:

Given : a^{3}+b^{3} -3a^{2} +7ab^{2}- 4a^{3} -3a^{2} b+ab^{2} -b^{2}  

To find : The solution of above expression.

Solution:

  • The given expression is,

     a^{3}+b^{3} -3a^{2} +7ab^{2}- 4a^{3} -3a^{2} b+ab^{2} -b^{2}  

  • Subtraction is one of the important arithmetic operation among division, multiplication,addition and subtraction in mathematics.
  • With the help of subtraction, we can find the difference between two quantities.
  • One thing to be noted that, to do subtraction of two terms, their variables and their powers should be equal.
  • The given expression is,

       a^{3}+b^{3} -3a^{2} +7ab^{2}- 4a^{3} -3a^{2} b+ab^{2} -b^{2}

                = -3a^{3} +b^{3}-3a^{2}-3a^{2}b  +8ab^{2}  -b^{2}

  • ∴ The solution for a^{3}+b^{3} -3a^{2} +7ab^{2}- 4a^{3} -3a^{2} b+ab^{2} -b^{2} is

-3a^{3} +b^{3}-3a^{2}-3a^{2}b  +8ab^{2}  -b^{2} .

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