Question

5)Sum of the zero's of p(x)=x²-7X+12 is.. *

urgent

1

4

7

12

​

Answer 1

Solution :-

⇒ x² - 7x + 12 = 0

By splitting middle term

⇒ x² - 4x - 3x + 12 = 0

⇒ x ( x - 4 ) - 3 ( x - 4 ) = 0

⇒ ( x - 3 ) ( x - 4 ) = 0

When x - 3 = 0

⇒ x = 3

When x - 4 = 0

⇒ x = 4

Sum of zeroes = 3 + 4 = 7

Other Method :-

Suppose α and β are the zeroes of the given polynomial , Now

★ α + β = - b / a

Here

a = 1 b = - 7

⇒ α + β = - ( - 7 ) / 1

⇒ α + β = 7 / 1

⇒ α + β = 7

Answer 2

$\huge\green{Solution}}$

We can find the answer by factoring the equation, then setting them up equal to zero.

$<b> x² - 7x + 12 = 0 </b>$

By middle term splitting

= x² - 4x - 3x + 12 = 0

= x ( x - 4 ) - 3 ( x - 4 ) = 0

= (x - 3)(x - 4) = 0

x - 3 = 0 x - 4 = 0

x = 3 x = 4

$<b> So you have two real solutions for the equation x² - 7x + 12 = 0 i.e. x = 3 , 4 </b>$